Curvature of a Plane Curve
Curvature of a circle c of radius R is the same for all points on the circle and equals κc=1/R. The circle is a curve of constant curvature, and we will use it to determine the curvature of other curves. When the radius of a circle gets smaller, the curvature is greater. Curvature of a straight line equals 0, and it can be interpreted as curvature of a circle with infinitely big radius.
In the pencil of tangent circles, there always exists one circle that has the property that one of the remaining 2(n-1) intersection points also coincide with T (the curve and this circle have 3 common points that coincide with T). In that case, we say that the curve and the circle have tangency of 2nd order at T. This circle is called osculating circle or circle of curvature of the curve k at the point T. We denote it ok(T). Curvature of a curve k at a point T equals the curvature of its osculating circle at T, i.e. κk(T)=κok(T) If the curve k is symmetric with respect to the normal line near the point T, then the osculating circle intersects this curve four times at T. In this case, we say that the curve and the circle have tangency of 3rd order, and we say this circle is hyperosculating circle. Osculating and hyperosculating circles of conicsTangent circle of a conic at a point T has 2 intersection points with the conic beside the point of tangency T. These remaining 2 points can be real and different, real but coincide in which case the conic and the circle have 2 points of tangency or they can be conjugate imaginary points. In all these cases, there is a neighborhood of T on the conic such that the arc of the tangent curve lies entirely on the same side of the conic in this neighborhood - in its interior or its exterior. Osculating circle of a conic is a unique circle for each point T on the conic. In this point T we have 3 intersection points of the conic and the circle so the circle must intersect the conic in one more real point beside T. This intersection point divides the osculating circle in two parts - one is the arc that lies in the interior, and the other is the arc that lies in the exterior of the conic. We can say that the osculating circle is tangent at T but also intersects the conic at T.
Hyperosculating circle of the conic is the tangent circle in a
vertex T of the conic. This is because the vertex of a conic lie on its axis of
symmetry and this axis of symmetry is also the normal line at this vertex. If the
circle is osculating in a vertex of the conic, due to the symmetry, the fourth
intersection point must also coincide with the vertex. The conic and this circle
have four common points at the vertex so they have no common points beside this
point. Therefore, all points of this circle beside T must lie entirely in the
interior or the exterior of the conic.
Figure 11 shows this properties. Figure 11
Every point of a conic has unique normal line and on this line an unique
point that is the center of the osculating circle of the conic. When a point
moves continuously along the conic, these centers of osculating circles form an
algebraic curve with the property that its tangent line is the corresponding
normal line of the conic. This curve is called the evolute of the conic.
Figure 12 Figure 13 shows constructions of the centers of osculating circles in a point on an ellipse, hyperbola or parabola.
Figure 13 Figure 14 shows constructions of centers of hyperosculating circles in a vertex of an ellipse, hyperbola and parabola. Figure 14 Created by Sonja Gorjanc, translated by Helena Halas and Iva Kodrnja - 3DGeomTeh - Developing project of the University of Zagreb, made with GeoGebra |