A line a is parallel to the plane of projection Π
and perpendicular to the line b. We need to prove that
their projections are also perpendicular, i.e. a' ⊥ b'. (Line a is parallel to the plane Π, while z is perpendicular to Π.) Proof can be written as: a ⊥ b & a | | Π => a ⊥ E => a' ⊥ E => a' ⊥ b'. |
n ⊥ P <=> p' ⊥ r1 & p'' ⊥ r2.
T ∈ Σ<=>d(A,T) = d(B,T) |
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The normal line and the1st steepest line through the pedal of the normal lie in the same horizontal projecting plane. | The normal line rotated into the plane Π1 is perpendicular to the 1st steepest line rotated as well, they intersect at the projection of the pedal. |
The normal line and the 2st steepest line through the pedal of the normal lie in the same vertical projecting plane. | The normal line rotated into the plane Π2 is perpendicular to the 2st steepest line rotated as well, they intersect at the projection of the pedal. |
Created by Sonja Gorjanc, translated by Helena Halas and Iva Kodrnja - 3DGeomTeh - Developing project of the University of Zagreb